25x^2+45x-9=0

Solution for 25x^2+45x-9=0 equation:

25x^2+45x-9=0

a = 25; b = 45; c = -9;
Δ = b2-4ac
Δ = 452-4·25·(-9)
Δ = 2925
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2925}=\sqrt{225*13}=\sqrt{225}*\sqrt{13}=15\sqrt{13}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(45)-15\sqrt{13}}{2*25}=\frac{-45-15\sqrt{13}}{50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(45)+15\sqrt{13}}{2*25}=\frac{-45+15\sqrt{13}}{50}
$